ProblemPermalink

Problem ID: 347

Title: Top K Frequent Elements

Difficulty: Medium

Description: Given an integer array nums and an integer k, return the k most frequent elements. You may return the answer in any order.

ThoughtsPermalink

This problem is relatively straight forward with C++’s ordered set.

SolutionPermalink

Find the frequency for each number O(N). Insert the number and frequency into an ordered set that orders the number by the frequency. Whenever the size of the set exceeds k remove the number with the lowest frequency.

ImplementationPermalink

class Solution {
public:
    vector<int> topKFrequent(vector<int>& nums, int k) {
        unordered_map<int,int> num_freq;
        for (const int num : nums) num_freq[num]++;
        
        set<pair<int,int>> most_freq;
        for (const auto& [num, freq] : num_freq) {
            most_freq.insert({freq, num});
            if (most_freq.size() > k) {
                most_freq.erase(most_freq.begin());
            }
        }

        vector<int> ans;
        for (const auto& [freq, num] : most_freq) {
            ans.push_back(num);            
        }
        return ans;
    }
};